Functions · Grades 11–11
Function Worksheets: Evaluating, Inverses & Transformations
f(4) just means replace every x with 4 and work it out. Function worksheets from evaluating linear and quadratic rules through finding inverse functions and describing transformations of the four parent functions (x, x², √x, 1/x).
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What it is
A function is a rule that assigns exactly one output to each input. f(x) is read 'f of x' and names that output for the input x. The inverse function f⁻¹(x) undoes f: swap x and y, then solve for y. For a linear function this always gives back another function, but for a quadratic it gives a ± relation with two outputs for most inputs, a function only once the original's domain is restricted. A transformation y = af(k(x − d)) + c stretches, reflects, and shifts the graph of a parent function like x, x², √x, or 1/x.
Why it matters
Once f(x) notation stops needing translation, a student can focus on what the function actually does instead of how to read it, which is the whole point going into calculus.
How to do it
- To evaluate: replace every x in the rule with the given input value, and simplify.
- To find the inverse: swap x and y, then solve the resulting equation for y.
- A quadratic's inverse: swap and solve the same way, but expect a ± square root. That's a relation, not a function, unless the domain is restricted.
- To describe a transformation: check the sign of a and k for reflections, |a| and |k| for stretches, then d and c for shifts.
Examples by level
- Beginnerf(x) = 2x + 8; f(1) =Answer10
- Intermediatef(x) = −7x − 4. Find f⁻¹(x) =Answerf⁻¹(x) = (x + 4) / -7
- Advancedf(x) = x² − 5x − 2; f(2) =Answer-8
Examples are generated by the same engine as the worksheets, so they're always mathematically correct. Built to avoid repeats, not reshuffle the same handful of questions.
Common mistakes
- Treating f(x) as f times x instead of 'f of x'.
- Substituting the input in some terms but not all.
- Sign errors when the input is negative (forgetting (−3)² = 9).
- Solving for the inverse but forgetting to swap x and y first.
- Mixing up which parameter controls a horizontal vs. a vertical change (k affects x, a affects y, even though both can look like a 'stretch').
- Assuming a quadratic's inverse is automatically a function: swap-and-solve gives a ± relation (two y-values for most x), a function only once the original's domain is restricted.
Tips
- f(x) is not f × x; it's the name of the rule applied to x.
- Wrap negative inputs in parentheses to keep signs and exponents right.
- In y = af(k(x − d)) + c, the letter k affects x (horizontal) and a affects the output (vertical), even though both can look like a 'stretch'.
- A quadratic's 'inverse' from swap-and-solve is usually a ± relation: write both branches rather than picking just one.
For parents
f(4) just means 'replace every x with 4 and work it out', the letter f names the rule, it isn't a multiplier.
For teachers
Insist on parentheses around substituted values, especially negatives, to prevent sign and exponent errors. For transformations, always evaluate the parameters in the same order: reflections, then stretches, then shifts.
Key vocabulary
- function
- a rule giving each input exactly one output
- input
- the value substituted for x
- inverse function
- the function that undoes f, found by swapping x and y and solving for y
- relation
- a set of input-output pairs; unlike a function, a relation can pair one input with more than one output. A quadratic's unrestricted inverse is a relation, not a function
- parent function
- the simplest form of a function family, e.g. f(x) = x² before any transformation
Frequently asked questions
- What does f(x) mean?
- It's function notation ('f of x') naming the output of the rule f for the input x. f(4) means the output when x is 4.
- How do you evaluate a function?
- Replace every x in the rule with the given number and simplify.
- How do you find the inverse of a function?
- Swap x and y, then solve the resulting equation for y. For f(x) = mx + b, the inverse is f⁻¹(x) = (x − b) / m.
- Is the inverse of a quadratic function also a function?
- No: swapping x and y in y = (x − h)² + k and solving gives y = h ± √(x − k), a ± relation with two outputs for most inputs, not a function. It only becomes a function if the original quadratic's domain is restricted first (e.g., to x ≥ h).
- What do a, k, d, and c control in y = af(k(x − d)) + c?
- a stretches/reflects vertically, k stretches/reflects horizontally, d shifts horizontally, and c shifts vertically.
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